x^2+31x-360=0

Solution for x^2+31x-360=0 equation:

x^2+31x-360=0

a = 1; b = 31; c = -360;
Δ = b2-4ac
Δ = 312-4·1·(-360)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-49}{2*1}=\frac{-80}{2}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+49}{2*1}=\frac{18}{2}
=9
$